40c^2-29c-18=0

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Solution for 40c^2-29c-18=0 equation:


Simplifying
40c2 + -29c + -18 = 0

Reorder the terms:
-18 + -29c + 40c2 = 0

Solving
-18 + -29c + 40c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-2 + -5c)(9 + -8c) = 0

Subproblem 1

Set the factor '(-2 + -5c)' equal to zero and attempt to solve: Simplifying -2 + -5c = 0 Solving -2 + -5c = 0 Move all terms containing c to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 2 + -5c = 0 + 2 Combine like terms: -2 + 2 = 0 0 + -5c = 0 + 2 -5c = 0 + 2 Combine like terms: 0 + 2 = 2 -5c = 2 Divide each side by '-5'. c = -0.4 Simplifying c = -0.4

Subproblem 2

Set the factor '(9 + -8c)' equal to zero and attempt to solve: Simplifying 9 + -8c = 0 Solving 9 + -8c = 0 Move all terms containing c to the left, all other terms to the right. Add '-9' to each side of the equation. 9 + -9 + -8c = 0 + -9 Combine like terms: 9 + -9 = 0 0 + -8c = 0 + -9 -8c = 0 + -9 Combine like terms: 0 + -9 = -9 -8c = -9 Divide each side by '-8'. c = 1.125 Simplifying c = 1.125

Solution

c = {-0.4, 1.125}

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